Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

Direct Variation Help?

OpenStudy (anonymous):

Is this a direct variation: -12x=6y (show steps please) If so, what is the constant of the variation

OpenStudy (anonymous):

any help..anyone

OpenStudy (johnweldon1993):

If something is varying directly...it is in the form y = kx Here you have -12x = 6y can you make your equation look like the first one?

OpenStudy (anonymous):

Okay. 6y=-12x Right?

OpenStudy (johnweldon1993):

Almost... notice how you have 6y = something the direct variation equation is just 'y' = something...so what can you do to isolate your 'y'?

OpenStudy (anonymous):

divide 6y by 6 so... y= - 2x?

OpenStudy (johnweldon1993):

That would be correct! So now you have y = -2x compared to y = kx 'k' = the constant of variation ...so your 'k' is ...?

OpenStudy (anonymous):

-2?

OpenStudy (johnweldon1993):

Correct again!

OpenStudy (anonymous):

How do i know that this equation is a dircet variation though. I know it is, but I guess i have to show my work :T

OpenStudy (johnweldon1993):

I'm not sure exactly how to explain it...other than you can see it is in the form of y = kx if it were varying inversely for example...it would have to be in the form y = k/x So yeah, not too sure how to show work to say it is in the correct form...

OpenStudy (anonymous):

okay thank you anyways. you helped alot!

OpenStudy (johnweldon1993):

Anytime!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!