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Mathematics 15 Online
ganeshie8 (ganeshie8):

@FutureMathProfessor

OpenStudy (anonymous):

Yes

ganeshie8 (ganeshie8):

2 (mod 2) = 0

OpenStudy (anonymous):

If 2 (mod 2) = 0, then how does 2 (mod 1) = 0? Wouldn't 2 (mod 1) DNE?

OpenStudy (lena772):

chocolate

OpenStudy (charlotte123):

http://www.wolframalpha.com/input/?i=2+%28mod+2%29+ <-----

ganeshie8 (ganeshie8):

by definition, x = y (mod k) => k | (x-y)

ganeshie8 (ganeshie8):

thats the oly definition we need to remember in modular arithmetic

OpenStudy (charlotte123):

2 (mod 3) however = 3

OpenStudy (anonymous):

^Wouldn't 2 (mod 3) simply be 2?

OpenStudy (anonymous):

Since the clock doesn't reset till 3

OpenStudy (charlotte123):

@FutureMathProfessor Exactly :P

ganeshie8 (ganeshie8):

thats right 2 (mod 3) = 2 2 (mod 3) = -1 also

OpenStudy (charlotte123):

^

OpenStudy (anonymous):

Couldn't 2 (mod 3) be -4 as well?

ganeshie8 (ganeshie8):

ok, say x = 2(mod 3) => 3 | (x-2) => x-2 = 3k x = 3k+2

ganeshie8 (ganeshie8):

k =all integers

ganeshie8 (ganeshie8):

just refer to the definition : x = y (mod k) => k | (x-y

OpenStudy (kainui):

I feel like a good example similar to this is, what is x? 0=sin(pi*x)

ganeshie8 (ganeshie8):

thats a good example, touches periodic thingy :)

OpenStudy (anonymous):

x [- z

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