Find the equation of the line below. Arrange your answer in the form y = mx + b, where b is the constant.where (-2,2),(2,-2)
These questions may help you: (a) What is the slope of the equation? (b) Can you express the equation in point-slope form? (c) Can you convert that to slope-intercept form? Wish you all the best :D
I am having the problem solving this question
Where are you stuck, a b or c?
Kind of all of them.i have trouble this kind of thing
well let me just say c i guess.
If you are given two points, you can calculate the slope with the following formula: \[\Large m=\frac{\color{green}{y_2}-\color{blue}{y_1}}{\color{green}{x_2}-\color{blue}{x_1}}\]
so would the answer be 0 because all of the coordinates are all 2
You still have to plug the coordinates in, 2 and -2 are different :)
oh,duh. now i understand.then i would divide the answer i get from subtracting the coordinates
What have you got now then? :)
i have -1?
yep, the slope is -1. Do you remember the point-slope form?
isn't -1 the point slope form?
-1 is the slope, not "the equation of the line in point-slope form".
http://zonalandeducation.com/mmts/functionInstitute/linearFunctions/psPic.gif
so how would i find the point-slope?
You would plug a point in the line named (x1,y1) and the slope named m in the following equation: \[y-y_1=m(x-x_1)\]
so i would put, y-(-2)=1(x-(-2)?
firstly, (a) which point did you choose? (b) what was the slope again?
the slope was -1 and i choose point -2
a point has both an x-coordinate and a y-coordinate, one number doesn't make a point :)
so i should have put -2 and 2?
yes, -2 as x1 and 2 as y1
sorry I got to go now, if you want to check, the answer is y=-x, cya :D
thanks
Join our real-time social learning platform and learn together with your friends!