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OpenStudy (kc_kennylau):
\[\int\tan x\tan 2x\tan 3x dx\]
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OpenStudy (raden):
let's start from this identity : tan(3x) = tan(2x + x) tan3x = (tan2x + tanx)/(1 - tan2xtanx) cross multiply, get tan3x (1 - tan2xtanx) = tan2x + tanx tan3x - tanxtan2xtan3x = tan2x + tanx tanxtan2xtan3x = tan3x - tan2x - tanx therefore, the integral above it same like |dw:1387803171000:dw|
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