Another Question!
first, find the negative reciprocal of that slope -3/2
2/-3?
\[m_p= (\frac{ -1 }{ 1 })*(\frac{ 2 }{ -3 })=\frac{ 2 }{ 3 }\]
where m is the slope and p is the perpendicular, mp is the perpendicular slope
the perpendicular slope is 2/3
now, let's use the point slope formula \[y-y_1=m(x-x_1)\] and plug in the slope and the given passing point m=2/3 x1= 3 y1= 9
is it B?
\[y-y_1=m(x-x_1)\] \[y-9=\frac{ 2 }{ 3 } (x-3)\] \[y-9=\frac{ 2 }{ 3 }*x - (\frac{ 2 }{ 3 }*3) \] i distributed 2/3 with x and 3
\[y-9=2/3x-6/3\] now add 9 to both sides \[y-9+9=2/3x-(6/3 )+9\]
ok
\[y=\frac{ 2 }{ 3 }x-\frac{ 6 }{ 3 }+9= \frac{ 2 }{ 3 }x-\frac{ 6 }{ 3 }+\frac{ 27 }{ 3}\]
\[y=\frac{ 2 }{ 3 }x+\frac{ 21 }{ 3 }\] \[y=\frac{ 2 }{ 3 }x+7\] answer
thats not a choice??
oh i see, that's because you need to convert the equation into the y=mx+b to see if they all equal to the answer i stated above. Here, i'll do it
you need to put it in standard form Ax + By = C
y = 2/3x + 21/3 -- multiply this by 3 3y = 2x + 21 -- subtract 2x from both sides -2x + 3y = 21 I would have made x positive by multiplying it by -1, but when I do that, it turns the line to : 2x - 3y = -21 and that is not an answer choice. So your answer is : -2x + 3y = 21
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