Question

calculate the average rate of change for the function f(x)=-x^4+4x^3-2x^2+x+1 from x=0 to x=1

Answer 1

compute\[\frac{f(1)-f(0)}{1-0}\]

Answer 2

so the answer i 1? @Zarkon

Answer 3

No, show your work.

Answer 4

f(1)-f(0)/1-0
that would be 0 @agent0smith

Answer 5

MERRY CHRISTMAS EVERYBODY!!

Answer 6

No. When I said show your work, I mean, find f(1), and find f(0).

What is f(1) = ?

What is f(0) = ?

Answer 7

f(1)=2
f(0)=0 @agent0smith

Answer 8

You're using -x^4+4x^3-2x^2+x+1 and plugging in x=1 for f(1) right? Those aren't correct.

Answer 9

oh no i wasnt!! well i just sis it now and got 7? that seems weird though so i hope its right

Answer 10

Then... how did you get f(1) and f(0)..???

7 isn't right.

What is f(1) = ?

What is f(0) = ?

Answer 11

i thought 1 and 0

Answer 12

f(1) means plug in x=1 into the function, -x^4+4x^3-2x^2+x+1.

f(0) means plug in x=0 into the function, -x^4+4x^3-2x^2+x+1.

Answer 13

ohh so its both 1!!

Answer 14

er.. what's both?

Answer 15

i mean they both equal 1

Answer 16

No. \[\Large f(1)=-(1^4)+4(1)^3-2(1)^2+1+1 = ???\]

Answer 17

-1+4-2+1+1 = 3

Answer 18

what do we do next

Answer 19

Now from that, can you tell me what f(1) is? And f(0)?

Answer 20

1 and 2

Answer 21

No, f(1) is not 1, f(0) is not 2. I already calculated f(1) above for you.

Answer 22

Show EXACTLY what you are doing to find f(0) and f(1). Like I did above.

Answer 23

\[\Large f(1)=-(1^4)+4(1)^3-2(1)^2+1+1 = ???\] \[\Large f(0)=-(0^4)+4(0)^3-2(0)^2+0+1 = ???\]

Answer 24

@agent0smith I wish you luck - You are going to need It...........badly >.>

Answer 25

that wasnt nice

Answer 26

@helpineedit Everyone needs luck! :)