A softball with a mass of 0.11 kg moves at a speed of 12 m/s. Then the ball is hit by a bat and rebounds in the opposite direction at a speed of 15 m/s . What is the change in momentum of the ball?

Question

wach · Answer

Do you know what momentum p is equal to?

wach · Answer

Also I assume 'bullet' is a ball actually?

awesome781 · Answer

It is softball.... sorry typo

awesome781 · Answer

No I don't know what momentum p is.....

wach · Answer

momentum = p = mv = mass * velocity
Mass is constant but the force of the bat causes the ball to accelerate to a different velocity 
When finding change in something, we find the difference or change in magnitude and divide that by the initial magnitude

awesome781 · Answer

Ok

wach · Answer

The initial momentum = m1v1 = 0.11kg*12m/s = 1.32 
Final = m1v2 = 0.11*15 = 1.65
Change = 1.65 - 1.32 = 0.33
0.33 kg*m/s is the change in momentum

awesome781 · Answer

Thank you

wach · Answer

If you need it as a percentage divide 0.33 by 1.65 
no problem :)

awesome781 · Answer

Ok...I got it!