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Mathematics 20 Online
OpenStudy (anonymous):

Find the maximum and the minimum values of th function. y=2sin(x)+sin^2(x)

OpenStudy (anonymous):

First find y' i.e., differentiate the let y=2sin(x)+sin^2(x) then y'=2cos(x)+2sin(x)cos(x) then for maximum or minimum y'=0 i.e., is 2cos(x)+2sin(x)cos(x)=0 then find the values.....

OpenStudy (anonymous):

then subtitute this values in y'' then you will get max and min...

OpenStudy (anonymous):

no need to find f" , stop at f' that's enough to consider max/min. don't forget + 2kpi (since it 's a period function)

OpenStudy (anonymous):

No you have to substitute f'(i.e., y') values in f'' (i.e., y'')

OpenStudy (anonymous):

why? f" is used to find out concavity , inflection points and consider the relative max/min. However, for the part relative max/min, this f" just to know there is some max/min or not, it doesn't show the value of max/min

OpenStudy (raden):

Hint : y=2sin(x)+sin^2(x) it would be minimum when sin(x) = -1 and it would be maximum when sin(x) = 1

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