which polynomial identity will prove that 37=64-27? difference squares difference of cubes sum of cubes square of a binomial
if u r confused...d best way is to apply each option....64 is a square of what? or cube of what?
\[37=4^3-3^3\]
I would therefore think B.
Guys makes sense?
yes i think it does
are u getting it @helpineedit
OK, other questions then?
what about for (3+6)^2=81 what would that be?
\[ (3+6)^2=81\]\[ (3+6)^2=9^2\]you guesses?
sum of cubes?
cubes, where do you see cubes?
I see squares, no?
difference in squares then sorry
Difference is subtracting, and you are not subtracting.
see u r talking about polynomial identities...tell me what all identities u know?
square of a binomial
@SolomonZelman
and ik difference squares difference of cubes sum of cubes square of a binomial @shrutipande9
The square of a binomial is always a trinomial.
it has to be the sum of cubes then
Binomial is something like 4x+16 it involves a variable and your question does not. Difference of squares is just (a+b)(a-b)=a^2-b^2 Sum of cubes. a^3 + b^3 = (a + b)(a^2 – ab + b^2) Difference of cubes. a^3 – b^3 = (a – b)(a^2 + ab + b^2)
\[(3+6)^2=81\] doesn't really look like any of those.
i know but it has to be i just dont know which one i though sum of cubes but i guess i was worng
square of a binomial, 3^2 + 2*3*6 +6*2 = 81 the best among choices
6^2 ***
Yeah, it is far far from the truth though. It is invalid.
(3+6) is not a binomial, and will never be it.
the question just asks for ploynomial identity which will prove that.
Well, it's not called a square of a binomial, is it?
I agree it's the best choice, but the choices are all very bad.
(3+6)^2 using the polynomial identity of square of binomila = 3^2 + 2*3*6 +6^2 = 81 hence proved.
I can see this somewhat.
:)
I would not do that type of problem out of principle, if I god forbid had it.
Join our real-time social learning platform and learn together with your friends!