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Mathematics 11 Online
OpenStudy (anonymous):

ill medal & fan :)

OpenStudy (anonymous):

OpenStudy (nurali):

0 = –16t2 + 36t + 4.

OpenStudy (anonymous):

set \[-16^2+36t+4=0\] and solve but i would do some simple algebra first

OpenStudy (anonymous):

thanks!

OpenStudy (nurali):

Anytime.

OpenStudy (anonymous):

divide all by \(-4\) and solve \[4x^2-9x-1=0\]

OpenStudy (anonymous):

can you help me with this one?

OpenStudy (anonymous):

that way the arithmetic will be easier when you use the quadratic formula the numbers are smaller

OpenStudy (anonymous):

\[2x^2-8x+7=0\] is the first step

OpenStudy (anonymous):

then one more time it is \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \[a=2,b=-8,c=7\]

OpenStudy (anonymous):

okay! which of the above do you think is the answer

OpenStudy (anonymous):

i don't know i didn't do it hold on

OpenStudy (anonymous):

ok!

OpenStudy (anonymous):

i get \[2\pm\frac{\sqrt2}{2}\] lets see whichone we can match it up with

OpenStudy (anonymous):

oh, that is already one answer ok go with that one

OpenStudy (anonymous):

THANKS:) i have two more questions:/ could you help mee?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

OpenStudy (anonymous):

lets try this \[x^2+6x=-7\\ (x+3)^2=-7+9=2\\ x+3=\pm\sqrt2\\ x=-3\pm\sqrt2\]

OpenStudy (anonymous):

that method is called "completing the square" as in turn \(x^2+6x\) in to a perfect square by adding \(9\) to both sides, making the left \((x+3)^2\) and the right \(-7+3^2\)

OpenStudy (anonymous):

okay! thanks.

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

one more!

OpenStudy (anonymous):

oh good

OpenStudy (anonymous):

OpenStudy (anonymous):

\[x^2-7x+5=0\] etc

OpenStudy (anonymous):

since \(-b\) is \(7\) you can ignore C and D

OpenStudy (anonymous):

in this case \(b^2-4ac=49-20=29\) i would go with B

OpenStudy (anonymous):

thank you so much. :)

OpenStudy (anonymous):

yw why math on xmas eve??

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