Question

How would you solve this?

Answer 1

F=[(6.67 E - 11 N*m^2/kg^2)(6.0 E 24kg)(2.0 E 30kg)]/(1.5 E 11m)^2

Answer 2

My teacher says it is "easy" but "messy", and i don't know what she means by that

Answer 3

The answer is suppose to be F = 3.6 E 22 N

Answer 4

If it helps, this is about Newtons Universal Gravitation

Answer 5

Overall, i don't know if this could be solved by hand or do i need a scientific calculator?

Answer 6

@TuringTest @ash2326 can any of you guys help me please?

Answer 7

\[F=\frac{(6.67 \times 10^{ - 11} Nm^2/kg^2)(6.0 \times 10^{24}kg)(2.0 \times 10^{30} kg)}{(1.5 \times 10^{11}m)^2}\]
Let's separate the units and numbers
\[F=\frac{6.67\times 10^{-11}\times 6\times 10^{24}\times 2\times 10^{30}}{1.5\times 10^{11}}\times \frac{{N\times \frac{m^2}{kg^2}\times kg\times kg}}{m^2}\]
Can you try from here? it can be solved with hand

Answer 8

Ok but first where did the E go?

Answer 9

is E suppose to equal 10?

Answer 10

yes, E stands for exponential
\[2E3= 2\times 10^3\]

Answer 11

...

Answer 12

so E is 10, and 2E^3 is 2 * 10^3

Answer 13

yes

Answer 14

and if i evaluate the first half, it would be 5.336 * 10^33

Answer 15

Also, any time you do a calculation where units are involved, do the calculation with only the units like this to make sure the units of your answer line up. This is called dimensional analysis and it is your best friend!

\[\frac{ [\frac{ Nm^2 }{ kg^2 }][kg][kg] }{ [m]^2 }=[N]\]

So yep, units of force is all that's left, which is a great sign you're on the right track.