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Mathematics 19 Online
OpenStudy (anonymous):

f(x) = I x-2 I ( Absolute value of x-2) Use the defination of the derivative to show that f'(2) does not exist.

OpenStudy (kc_kennylau):

That means using the first principle :) Try evaluating the value of \(\huge\lim\limits_{h\rightarrow0}\frac{|x+h-2|-|x-2|}h\)

OpenStudy (kc_kennylau):

Hint: Seperate it into cases?

OpenStudy (kc_kennylau):

you'll find that some cases lead to 1 while some lead to -1.

OpenStudy (anonymous):

oh yeh, I did that, I differentiated using 1st principles -x+2, and also x-2. I got the values of -1 and 1 respectively. So, because they are not the same, can I therefore conclude that it does not exist?

OpenStudy (kc_kennylau):

yep :)

OpenStudy (anonymous):

thanx a million kc.

OpenStudy (kc_kennylau):

no problem at all :D

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