Question

Find the integral of sqrt(x^2-2x+1) dx from 0 to 1. (Answer: 1/2)

Answer 1

factor the integrand

Answer 2

sqrt(x^2-2x+1)= sqrt(x-1)^2 so that leaves (x-1)dx from 0 to 1

Answer 3

And then?

Answer 4

= [(x^2)/2] from 0 to 1 = 1/2

Answer 5

do you get it?

Answer 6

So the integral of (x-1) dx is not x^2/2-x?

Answer 7

sorry im drunk i will tell you now the correct one :D

Answer 8

its absolute(x-1) because we too sqrt off so from 0 to 1 absoulute(x-1) = -x+1

so the integral becomes [x-(x^2)/2] from 0 to 1 = 1/2 :D

Answer 9

took*