Question

1.

Answer 1

\[1/25=5^{x+4}\]

Answer 2

Take the log of both sides to bring the exponent down.
you would then get:
\[\huge \log \frac{ 1 }{ 25 } = \log 5 * (x+4)\]

Answer 3

ok why do you take logs and what are they?

Answer 4

Log = logarithm
The logarithm of a number is the exponent to which another fixed value, the base, must be raised to produce that number.

Answer 5

Shamil, try using exponential properties, using logarithms is ok, but I believe the properties can solve this quite easy.

Answer 6

x+4 the eponent comes down after you log?

Answer 7

\[\frac{ 1 }{ 25 }=5^{x+4}\]
because of 1/a^n = a^-n
and 25 = 5^2
\[5^{2}=5^{x+4}\]
because I have the same base, I can just work with the exponents, all you have to do is solve this equation:
\[2=x+4\]

Answer 8

5^-2 = 1/25
not 5^2

Answer 9

oh yeah, it's -2, Imz zowy

Answer 10

and yes you can use that method as well

Answer 11

Well yeah, methodically talking, no matter wich way we do it, It should give us the same answer.

Answer 12

Since you are asking to learn about exponential functions, i guess that method would probably more efficient, or does this topic of course use logs?

Answer 13

so should I use log method or the other method im confused

Answer 14

You can use wichever you want or feel it's easier to apply and understand.

Answer 15

Are you supposed to use exponential rules or use logarithm rules?

Answer 16

yes it does use log but not for this lesson only exponential rules

Answer 17

Okay, then you would use his method.

Answer 18

ok Shamil can you please explain his method?

Answer 19

Turn the other side( one without the x into a 5 into the power of.... Which would be -2.