LIMIT
x---infinite xSin(1/x)

as x approaches negative infinity

Question

LIMIT
x-->-infinite      xSin(1/x)      

as x approaches negative infinity

ikram002p · Answer

asume x= 1/y
y=1/x
when x goes to -infinit y goes to 0
LIMIT x-->-infinite xSin(1/x) 
limit sin y /y as y goes to zero =1

ikram002p · Answer

so in other words the trick is in changing the limit? yess change the limit

anonymous · Answer

uhmmm, i had to delete my comment thinking that i have observed wrongly.

anonymous · Answer

thanx ikram002p. I still want to fint out  something from you though, let me close this question.

ikram002p · Answer

dnt worry i somtimes give wrong answers too , so when u learn sothing there is no wrong question :o, ask wat u dnt got/knew/confused in

anonymous · Answer

ok, I will not close the question.Tell me what's going on here, if you have an Idea:

$$\lim_{\theta \rightarrow 0} Sin5\theta/3\theta    $$
$$= 5/3 \lim_{\theta \rightarrow 0}  ( \sin5\theta/5\theta)$$

$$= 1$$
$$How?$$

anonymous · Answer

no , I meant $$= 5/3 \times 1$$
$$= 5/3$$

ikram002p · Answer

ok u have
lim sin 5theta/ 3 theta  multiply by 5/5
lim 5×sin 5theta/ 5×3 theta
5/3 lim sin 5theta/ 5 theta 
 lim sin 5theta/ 5 theta =1
5/3 lim sin 5theta/ 5 theta =5/3×1

anonymous · Answer

oh, now I see, thanx again for your help. it was an example given here, and i could not take it in well on some stages. thanx.

ikram002p · Answer

ur wlc.