Check if im correct?? Write the equation of the line that has an x-intercept of -3 and passes through the point (-3, 7). x = -3 y = -3 y = 7 <--
nope :/
x-intercept is when y=0
So there would be no y pretty much
ohhh so since theres no y anymore it would be x=-7??
Pretty much Poor Kc :3
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SO, the solution to your problem is given as follows, combining with what has been said already: \[y= mx+ c\] this is the equation of the line as per your question, where \[m\] is the gradient obtained by \[m =\frac{y _{2} - y _{1} }{ x _{2}-x _{1} }\] \[c\] is the \[y\]intercept , where the line passes through the \[y\] axis. so, as per the graph above, you can actually see that you have two points \[\left( -3, 7 \right)\] and \[\left( -3,0 \right)\] you can now calculate the gradient, and fit in all the necessary numbers into the above equation of a straight line.
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