Write the equation of a line with the slope of -2 which contains the point (3,6)
Use the point slope formula: \[\LARGE y-y_{1}=m(x-x_{1})\]
Where m=slope and x1/y1 are (x, y)
Plug value of the slope and point ( -3 , 6 ) in Y = m x + b 6.00 = 3 + b b= 6 -3 b= 3 So the equation will be Y = -1 x + 3
slope is -2, not -1 Luigi
y = mx + b (3,6) x = 3 and y = 6 slope(m) = -2 now sub all of that into y = mx + b and solve for b
@texaschic101 what method is that?
you do not have to use point slope formula if it doesn't ask for point slope formula in the answer...you can just as easily use slope intercept formula
Alrighty
y = mx + b 6 = -2(3) + b 6 = -6 + b 6 + 6 = b 12 = b equation is : y = -2x + 12 or y - y1 = m(x - x1) y - 6 = -2(x - 3) y - 6 = -2x + 6 y = -2x + 6 + 6 y = -2x + 12 you will get the same answer either way. I just find it easier to use slope intercept, rather then point slope, unless it asks for point slope.
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