What is the axis of symmetry,x-intercept, and y-intercept of the equation, h(t)=-16t^2+64t+80?

Question

campbell_st · Answer

well start with the easy one, 

the vertical intercept ... let t = 0 and what you get for h(t)..?

next the t intercepts... 

let h(t) = 0 and then solve for t

then start by dividing every term by -16

and you'll find a quadratic that can be factored. 

for the axis of symmetry, its half way between the horizontal intercepts... 

or for a parabola

$$y = ax^2 + bx + c$$

the axis of symmetry can be found by 

$$t = \frac{-b}{2a}$$

in your question b = 64 and a = -16

hope this helps...