Question

using quadratic formula
solve:
x^2+7x=-3

Answer 1

start with
\[x^2+7x+3=0\] and use the quadratic formula
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]with \(x=1,b=7,c=3\)

Answer 2

im stuck on this part \[x= -7\pm \frac{ \sqrt{49}+12 }{2}\]

Answer 3

@satellite73

Answer 4

hmm

Answer 5

what do i do next?

Answer 6

-4ac => -4 * 1 * 3 \(\ne +12\)

Answer 7

\(\bf \text{quadratic formula}\\
x= \cfrac{ - b \pm \sqrt { b^2 -4ac}}{2a}\implies x= \cfrac{ - 7 \pm \sqrt { 7^2 -4(1)(3)}}{2(1)}\)

Answer 8

so... what would you get inside the radical?

Answer 9

hmm anyhow \(\bf \text{quadratic formula}\\
x= \cfrac{ - b \pm \sqrt { b^2 -4ac}}{2a}\implies x= \cfrac{ - 7 \pm \sqrt { 7^2 -4(1)(3)}}{2(1)}\\ \quad \\
x= \cfrac{ - 7 \pm \sqrt { 49 -12}}{2}\implies x= \cfrac{ - 7 \pm \sqrt { 37}}{2}\implies
\begin{cases}
\cfrac{ - 7 + \sqrt { 37}}{2}\\ \quad \\
\bf \cfrac{ - 7 - \sqrt { 37}}{2}
\end{cases}\)

Answer 10

you would get \[-7\pm \sqrt{49}+12\]
right?

Answer 11

\(\bf -4(1)(3)\implies -12\)

Answer 12

thank you!!! i see what i did wrong

Answer 13

yw