Question

would i be correct?

https://media.glynlyon.com/g_alg01_2013/3/83g.gif


y = -3/2x - 9/2 <<
y = -2/3x + 9/2
y = 3/2x - 9/2

Answer 1

hmmmm which points did you use to get that?

Answer 2

ummmm im not sure ):

Answer 3

meaning, you haven't done the exercise
well.... to get the equation of the line, you'd need 2 points

Answer 4

yes

Answer 5

I can see right off, that ( -3, 0) works, as well as ( -1, -3) works too, so using those to get the equation \(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(-3\quad ,&0)\quad &(-1\quad ,&-3)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}
\\ \quad \\

y-y_1=m(x-x_1)\quad \textit{once you get the slope then just plug in}\\ \quad \\
\textit{the values here and solve for "y"}\)

Answer 6

the slope is -3/2?

Answer 7

yes and if you use that and the point at \(\bf x_1, y_1\) you'd end up with \(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(-3\quad ,&0)\quad &(-1\quad ,&-3)
\end{array}
\\\quad \\

slope = m= -\cfrac{3}{2}
\\ \quad \\

y-0=-\cfrac{3}{2}(x-(-3))\quad
\textit{and solve for "y"}\)

Answer 8

−3/2(x−(−3)) to solve this part is it distributive property?

Answer 9

yeap

Answer 10

\(\bf y-0=-\cfrac{3}{2}(x-(-3))\implies y=-\cfrac{3}{2}(x+3)\)

Answer 11

y= -3/2x-9/2?

Answer 12

yeap

Answer 13

thank you!

Answer 14

yw