Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

What is the relationship between <2 and <3 ?

OpenStudy (anonymous):

OpenStudy (anonymous):

@gummibear @ganeshie8 @Shogunwolf5 @ShadowLegendX @

OpenStudy (nikato):

Is Chicago and Ontario parallel?

OpenStudy (kc_kennylau):

interior angles

OpenStudy (kc_kennylau):

<2+<3=180

OpenStudy (anonymous):

@nikato yes , @kc_kennylau same side interior angles right ?

OpenStudy (nikato):

Yup^same side interior

OpenStudy (anonymous):

@nikato @kc_kennylau can you help me with another one please ?

OpenStudy (anonymous):

<JKN = <LKM because .. A. vertical angles are congruent , B . Reflective property .

OpenStudy (anonymous):

@kc_kennylau what does that mean ?

OpenStudy (kc_kennylau):

which school are you in? :)

OpenStudy (anonymous):

@kc_kennylau ga connexus academy

OpenStudy (kc_kennylau):

A

OpenStudy (anonymous):

@kc_kennylau can you explain it ?

OpenStudy (kc_kennylau):

http://www.math.com/school/subject3/images/S3U1L5DP2.gif this is the theorem

OpenStudy (anonymous):

@kc_kennylau but why wouldn't it be reflective property ?

OpenStudy (kc_kennylau):

reflective property states that an angle is congruent to ITSELF

OpenStudy (anonymous):

@kc_kennylau can you help me ONE more ?

OpenStudy (kc_kennylau):

ok give me a min i need to get dressed

OpenStudy (kc_kennylau):

sorry i have to go, @Callisto will help you :)

OpenStudy (nikato):

Ok, what is it?@Faith_Rochelle

OpenStudy (anonymous):

What information do I need to prove these triangles congruent by AAS Congruence Postulate ? I narrowed it down to <BAC = <DAC or <CBA = CDA . I can't decide between the two .

OpenStudy (nikato):

Actually with the diagram, BAC=DAC. And u should know that AC=AC by reflexive. So now that u know this, what else do u need for AAS?

OpenStudy (nikato):

<BAC=<DAC

OpenStudy (anonymous):

@nikato oh okay , thank you .

OpenStudy (nikato):

So do u know what other thing u need to prove AAS?

OpenStudy (anonymous):

@nikato wouldn't it be BAC = DAC ?

OpenStudy (nikato):

No, that's given

OpenStudy (nikato):

Based on the diagram , u have those two angles and 2 "sides" congruent. But in order to do AAS, u need 2 pair of angles and a sides to be congruent, so u still to show one more pair of angles congruent

OpenStudy (anonymous):

@nikato its not given on my diagram ??

OpenStudy (nikato):

Well, u should why AC=AC. With <BaC=<DAC, u see how in ur diagram, both of them are marked with the same number of arcs. It's just a way of saying they r equal

OpenStudy (anonymous):

@nikato so CBA and CDA ?

OpenStudy (nikato):

Yup

OpenStudy (anonymous):

@nikato do diagonals of a parallelogram always have to equal 180 ?

OpenStudy (nikato):

They should be becuz thy are lines or line segments if that's what ur talking about

OpenStudy (anonymous):

@nikato can you help me with another one about angle relationships ?

OpenStudy (nikato):

sure

OpenStudy (anonymous):

<1 and <2

OpenStudy (anonymous):

@nikato what is their relationship is the question .. the choices are : A. Adjacent B. Linear pairs. C. supplementary D. vertical

OpenStudy (nikato):

they r just adjacent

OpenStudy (anonymous):

@nikato why are they not linear pairs ?

OpenStudy (nikato):

u can take a look at this http://www.mathsisfun.com/geometry/adjacent-angles.html

OpenStudy (nikato):

theya re not linear because they dont form any striaght line or add up to 180

OpenStudy (nikato):

http://www.mathopenref.com/linearpair.html

OpenStudy (anonymous):

@nikato okay also I am confused on this statemennt a square is ___ a rectangle . Isn't it sometimes a square is a rectangle but a rectangle is always a square ? @nikato

OpenStudy (nikato):

its the other around

OpenStudy (nikato):

a square can always be a rectangle but a rectangle can sometimes be a square

OpenStudy (nikato):

becuz square=parallelogram with 4 right angles and all 4 sides congrunet rectanlge= parallelogram with 4 right angles

OpenStudy (nikato):

|dw:1388121918140:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!