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Find the limit. lim as x approaches 0 (x^3+12^2-5x)/(5x) a) 5 b) -1 c) 0 d) does not exist
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are you sure it is 12^2 in the numerator .??
plug in x=0 to top and bottom, what do you get ?
it will be undefined because the denominator becomes \[zero\]
*12x^2
\[-1\]
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thanks!
yeahh ..12x^2 is better ..:)) divide the numerator and denominator by x and then plug into the limit
the answer must be -1
take out x on top to remain with\[\frac{x(x ^{2} +12x -5)}{ 5x }\] cancel out x on top and bottom, and the plug in zero in place of x. You will remain with \[\frac{ -5 }{ 5 } = -1\]
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