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lim sq rt. of x^2-9 lim as x approaches 16 a) sq. rt. 247 b) 123.5 c)+- sq rt. 247 d) does not exist
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\[\huge \lim_{x \rightarrow 16} {\sqrt{x^{2}-9}} = \sqrt{16^2-9} = ?\]
option a is correct
don;t just give answers, try leading them to it :D @nirmalnema
you have given that so why will i give the same thing again
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