Question

Which equation is correct for the perpendicular bisector of the line segment whose endpoints are (4,-3) and (8,3)?
1.) y-3= -2/3(x-6)
2.) y+3= 2/3(x-6)
3.) y= 2/3(x+6)
4.) y= -2/3(x-6)

Answer 1

take the slope of the two points.
and input into the formula:
y - y1 = m(x-x1)
where (4,-3) -->(x1,y1)
and m = slope

Answer 2

I got to the ACTUAL equation which is y=-2/3x+4. I just have no idea about these choices.

Answer 3

Uhhh.. hold up.

Answer 4

The actual slope or the reciprocal slope?

Answer 5

actual slope

Answer 6

The actual slope is 3/2

Answer 7

The reciprocal is -2/3

Answer 8

Yeah that doesn't make much sense. When I did what you said I got:
y--3= -2/3 (x-4)

Answer 9

then u want to find the midpoint of those 2 points

Answer 10

The uhh midpoint is (6,0)

Answer 11

so now find the equation with the new slope and that point^

Answer 12

I did the SRME method.
S(slope)= 3/2
R(reciprocal)= -2/3
M(midpoint)= (6,0)
E(equation)= y=-2/3x+4

Answer 13

how did u get that equation? i think u did something wrong. i actually got one of ur choices

Answer 14

Uhmm because I did:
y=-2/3x+b
0=-2/3(6)+b
0=-4+b
b=4
So then plug it all in together:
y=-2/3x+4

Answer 15

But its not one of the choices

Answer 16

try plugging it in in the point slope equation

Answer 17

The what?

Answer 18

point slope equation