Question

lim as x approaches infinity

(8x^3-3x^2+3x)/(-x^3-2x+7)

a)infinity b)3/2 c)-8 d)8

Answer 1

for 8 and -8, you could just substitute x=8, as you are not getting a zero in the denom

Answer 2

thanks

Answer 3

and as for infinity, if you divide
8x^3 - 3x^2 +3x by the denominator,
you'll get
8(-x^3 - 3x +7) - 3x^2 - 13x ..
so that should simplify things a bit