Jake has proved that a function, f(x), is a geometric sequence. How did he prove that?

He showed that an explicit formula could be created.

He showed that a recursive formula could be created.

He showed that f(n) ÷ f(n - 1) was a constant ratio.

He showed that f(n) - f(n - 1) was a constant difference.

Question

Jake has proved that a function, f(x), is a geometric sequence. How did he prove that?

 He showed that an explicit formula could be created.

 He showed that a recursive formula could be created.

 He showed that f(n) ÷ f(n - 1) was a constant ratio.

 He showed that f(n) - f(n - 1) was a constant difference.

hartnn · Answer

in geometric series, 
RATIO of current term f(n) to previous term f(n-1) is CONSTANT :)

hartnn · Answer

key words are, CONSTANT, RATIO

anonymous · Answer

So then it would be D? :D

hartnn · Answer

D had "difference" in it! 
C had constant ratio in it :)

anonymous · Answer

f(n)=arn−1,n∈Z+

He showed that f(n) ÷ f(n - 1) was a constant ratio.

anonymous · Answer

Opps XD Yeah, sorry!! Haha! Thank you for explaining!

anonymous · Answer

I dont know who to give the best response to :/

hartnn · Answer

i'm not here for medals. you understand, thats my medal :)

anonymous · Answer

^ That is the best medal.

anonymous · Answer

Thank you! But I think to make it fair, since you, Hartnn got a medal. I would like to give it to @Trojan .If thats okay?

hartnn · Answer

no problem at all :)

anonymous · Answer

Thank you guys for helping me!

anonymous · Answer

No problem :)

hartnn · Answer

you're most welcome ^_^