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Mathematics 10 Online
OpenStudy (anonymous):

In desperate need of help. Fan and Medal

OpenStudy (anonymous):

Gordon is evaluating some stocks he wants to purchase. You can see the function of the stock price below. The variable x represents days. Stock A: f(x) = 25(1.08)x B: x f(x) 0 22.00 1 21.56 2 21.13 C: The initial price of this stock is $30, but it has been increasing 4% each day. 1.) Create the price function for Stock D. It should have the second lowest starting price and the second highest rate of growth. Using complete sentences, justify that your function meets these requirements. 2.) Graph the price function for Stock D. Explain the key features of the graph with complete sentences. 3.) A recent drop in sales has affected Stock D with the function g(x) = –6. Explain to Gordon how Stock D’s new price function, f(x) + g(x), will be created. Graph f(x) + g(x). 4.) Gordon wants to fully understand what kind of changes could affect the money he is investing. Using complete sentences, explain the effect of the following transformations. Graph them and f(x) on the same coordinate plane. f(x + 2) f(–x) f(x) + 3

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

@Luigi0210

OpenStudy (anonymous):

This is hard ... but as soon as I find the answer I tell you what ...ok?

OpenStudy (anonymous):

Ok, thank you

OpenStudy (anonymous):

@MERTICH

OpenStudy (anonymous):

ha ha ha, I was offline a bit . Let me c what's going on

OpenStudy (anonymous):

Ok, thanks

OpenStudy (anonymous):

@Trojan

OpenStudy (anonymous):

@Baseballa101 I tried to solve it but I couldn't figure it out. I'm sorry :(

OpenStudy (anonymous):

Ok, thanks anyway

OpenStudy (anonymous):

Uhmmm, a tricky one indeed. Ok, to answer question (a), the price function of stock D, given that price is increasing by 4% each day, I am not sure about anything here, but maybe we can come out with something, is that exponential rise in price, or it is 0.4% of $30? If it is 0.4% 0f $30 , then \[h(x) = 30 + (0.04 \times 30)x = 30+ 1.2x\] where x is the number of days. And attached is the graph for the above function

OpenStudy (anonymous):

But then, the words" rate of growth make me want to believe that this is exponential growth.

OpenStudy (anonymous):

Idk, I've been stuck on this for a LONG time and everyone I ask can't figure it out, or I get different answers

OpenStudy (anonymous):

@MERTICH where did you go??

OpenStudy (anonymous):

checking out exponentials brb

OpenStudy (anonymous):

OK, I believe it is a question on exponential. \[y(t)=a \times e ^{kt}\] Where y(t) = value at time "t" a = value at the start k = rate of growth (when >0) or decay (when <0) t = time

OpenStudy (anonymous):

so in our case it will be \[y(x) = 30\times e ^{1.2x}\]

OpenStudy (anonymous):

Is this still number 1??

OpenStudy (anonymous):

@Jordannyah can you help?

OpenStudy (anonymous):

ya, that is the first part. As I said, it's a question on rate of growth, it requires intense knowledge of exponentials.

OpenStudy (anonymous):

I'm not really good at exponentials

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