Question

Could anyone explain how to take the derivative of 10^(x^2-1)

Answer 1

so just 10^x as the 2-1 is 1?

Answer 2

Errr hold on I'll make it more clear.

Answer 3

\[10^{x ^{2}-1}\]

Answer 4

do you know how to take the derivative of \(f(x)=a^x\) ?

Answer 5

you would have to start with the chain rule

Answer 6

I'm pretty sure I've done something like that before but I'm blanking right now.

Answer 7

do you recall implicit differentiation?

Answer 8

Yup.

Answer 9

\[y=a^x\]\[\ln y=x\ln a\]\[\frac{y'}y=\ln a\]\[y'=y\ln a=a^x\ln a\]

Answer 10

Ah! I remember now! Thank you, I think I've got it now.

Answer 11

welcome, and don't forget to use the chain rule too :)