identify the oblique asymptote of f(x)=2x^2+3x+8/x+3
use polynomial division or synthetic division the oblique asymptote will be the quotient.. which is linear then ignore the remainder
I think it should have no oblique asymptotes but it has vertical asymptotes. If the highest power of the unknown is the numerator is smaller than that of denominator, it has no oblique asymptotes, I think.. (in this case, 1 in numerator is smaller than 2 in denominator) That's what I've learnt
wow.... here is the oblique asymptote |dw:1388206547184:dw| so the oblique asymptote is the quotient y = 2x - 3 attached it the graph showing the oblique asymptote Hope this helps... Its important to know that oblique asymptotes exist when the degree of the numerator is greater than the degree of the denominator here is a link that may assist http://www.purplemath.com/modules/asymtote3.htm
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