angle BAC is a right angle, angle DEC is a right angle, DB bisects AE, Prove C is the midpoint of DB
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Do u have a diagram for this problem?
I do, but I do not know how to put it on here. It is for a proof.
Right under the box to reply there's a button called draw. Click on that to draw ur diagram
|dw:1388271533376:dw|
Duh! Sorry!
Ok, and if u can, u see that pencil on the upper right corner of ur drawing, click it and draw it what's given based on the info u have
angle BAC is a right angle, angle DEC is a right angle, DB bisects AE, Prove C is the midpoint of DB
These are the "given" and I have come up with the following (but I am missing something more): Angle BAC is a right angle - Given Angle DEC is a right angle - Given Segment DB bisects Segment AE - Given Angle BAC equals Angle DEC - Right angles are congruent Segment DB bisects Segment AE (AC=CE) - Line bisector Triangle BAC = Triangle DEC - ASA CB=CD - CPCTC CB=CD - C is the midpoint of DB
Yes, ur r missing one step. U can't say SAS. U need a step before that becuz u only have SA. There r actuallyn2 ways to prove it HL or SAS. But if u r trying to prove SAS, u need another pair of congruent angle besides those right angle
|dw:1388272650847:dw|this is all u r saying. but u cant do ASA becuz all u have mentioned is AS
Thank you for your help.
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