If the fifth term of an arithmetic sequence is −5 and the ninth term is −17, the first term of this sequence must be? Would it be 7?
The \(n\)th term of an arithmetic sequence is \(a+d\times(n-1)\), where \(a\) is the first term and \(d\) is the common difference
Try to set up two equations from that :)
how would I do that if I don't have the first term nor the second term to find the common difference?
You set up two equations to find that
The first equation is \(a+d\times(5-1)=-5\)
Can you figure out the second equation by yourself? :)
Sooty to intrude. But I got 7 too
a+d X ( 9-1) = -17?
oh really? I was just guessing on that haha
exactly
now you have a system of equations: \[\left\{\begin{array}{lr}a+4d=-5&---(1)\\a+8d=-17&---(2)\end{array}\right.\]
ohhh not this thing haha ok
I got 7?
yep :) \[2\times(1)-(2):a=7\]
Thank you. You are the best
Thanks <3
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