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Mathematics 11 Online
OpenStudy (anonymous):

What is the average deviation of the following data set rounded to the nearest hundredth? 2.5, 1.4, 1.8, 2.5, 3.1, 1.02, 3.05

OpenStudy (anonymous):

Or, at least how do you find average deviation in general..?

OpenStudy (anonymous):

Step 1: Find the average value of 7 original values Average = \[\frac{ 2.5 + 1.4+ 1.8+2.5+3.1+1.02+3.05 }{ 7 }\]\[= 2.1957\] Step 2: Find distance of each value from that average Value --> Distance from Average (2.1957) 2.5 --> 0.3043 1.4 --> 0.7957 1.8 --> 0.3957 2.5 --> 0.3043 3.1 --> 0.9043 1.02 --> 1.1757 3.05 --> 0.8543 Step 3: Find the average value of those distances Average of distance (same to average deviation) ( \[ = \frac{ 0.3043 + 0.7957 + 0.3957 + 0.3043 + 0.9043 + 1.1757 + 0.8543 }{ 7 }\]\[\approx 0.6763\]

OpenStudy (anonymous):

2.03 2.20 2.5 Those are the only options for answers..

OpenStudy (anonymous):

I think my answer is good enough, except it should be modified to round of nearest hundredth. If my answer is wrong, so please check again the value of the original set. Anyway, that is the way to find out of average deviation.

OpenStudy (anonymous):

..I'm just saying that the number you gave isnt one of the multiple choice options.. .-.

OpenStudy (anonymous):

Yes, I see your point. But I cannot find the answer according to your options. Haha. You may believe or not, depend on you ;) I am sure my answer is correct according to the data set you gave at first time

OpenStudy (anonymous):

And 1 more thing, check your question again, if you did not ask for average deviation, i think you want to ask about average only. Therefore the answer is 2.20 of average value (NOT DEVIATION)

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