2nd to last question

Question

anonymous · Answer

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joannablackwelder · Answer

A vertical asymptote is where the denominator is equal to zero.

anonymous · Answer

@Xeph @linh412986 @ehuman

joannablackwelder · Answer

So, set the denominator equal to zero and solve for the x-values that make vertical asymptotes.

anonymous · Answer

@JoannaBlackwelder is right. Look at the denominator and set it to zero, and solve for x

anonymous · Answer

Nothing more to say, Joanna is right. Try to think a little bit. @hannahmichelleee

joannablackwelder · Answer

You will need to factor the quadratic into binomials.

anonymous · Answer

when I set it to 0 and solve I get -4,2 on my graphing calc.

joannablackwelder · Answer

Me too. :)

anonymous · Answer

Good, -4 and 2 are both correct answers

anonymous · Answer

so thats it!? :D I'm done with that equation?

anonymous · Answer

you shouldn't need a calculator for this problem. the denominator is $$x^2+2x-8$$set it to zero,$$x^2+2x-8=0$$then we factor. numbers that multiply to -8 and add to 2?

factors of 8 are 1,2,4,8 so we are looking at$$\pm 2,\pm 4$$but they add to +2, so we need +4, -2 so we have $$(x+4)(x-2)=0$$solving for x is trivial then, you have 2 solutions

anonymous · Answer

thank you all!!!

joannablackwelder · Answer

Yup, that 's it!