LAST QUESTION HOW DO I DO THIS!!!!!!
I like to help, but you're literally just copy pasting every question and letting others solve it for you.
No I want people to explain how to do it, this is my pretest I want to go in having some kind of idea on how to do it all
the question asks you about domain. what does that mean?
the bottom of the fraction
no the input
a function can be described in terms of both range and domain. what do those words mean?
input and output
which is input and which is output?
domain is the input and the range is the output
alright, so the question asks us what is the domain? \[H(w)=\frac{65}{w}\]then we are looking for what is permissable for input into this function? we input w.
look at the function and tell me what isn't okay for w. Keep in mind, we are talking about width of a real object. What are permissable widths in this function?
is it w>0
Don't guess, answer my question. What could the width of the object be? Let's try -9.5. Can we have an object with -9.5 width?
no
I honestly think its that, it has to be greater than 0
think of it in terms of mathematics though. What would happen if we had w=0 in that function?
we've already eliminated w<0
but it doesnt say less than or equal to, it just says greater than
ignore the multiple choice answers for now, we need find the permissible values for w.
we know w can't be less than zero, since that won't make sense for a real object.
if w isn't smaller than zero, it's either zero, or bigger than zero.
so we need to elminate zero as a possibility.
what does the function tell you that lets you do this?
@Xeph ... you are great at explaining things!
thanks.
the H(w)?
\[H(w)=\frac{65}{w}\]
why can't w be zero?
because anything times 0 is zero
it's because when you divide by zero, everything breaks
simply speaking
same reason we found asymptotes in your last question, when the denominator was zero
therefore, w>0
thanks
you're welcome
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