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Mathematics 13 Online
OpenStudy (anonymous):

LAST QUESTION HOW DO I DO THIS!!!!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

I like to help, but you're literally just copy pasting every question and letting others solve it for you.

OpenStudy (anonymous):

No I want people to explain how to do it, this is my pretest I want to go in having some kind of idea on how to do it all

OpenStudy (anonymous):

the question asks you about domain. what does that mean?

OpenStudy (anonymous):

the bottom of the fraction

OpenStudy (anonymous):

no the input

OpenStudy (anonymous):

a function can be described in terms of both range and domain. what do those words mean?

OpenStudy (anonymous):

input and output

OpenStudy (anonymous):

which is input and which is output?

OpenStudy (anonymous):

domain is the input and the range is the output

OpenStudy (anonymous):

alright, so the question asks us what is the domain? \[H(w)=\frac{65}{w}\]then we are looking for what is permissable for input into this function? we input w.

OpenStudy (anonymous):

look at the function and tell me what isn't okay for w. Keep in mind, we are talking about width of a real object. What are permissable widths in this function?

OpenStudy (anonymous):

is it w>0

OpenStudy (anonymous):

Don't guess, answer my question. What could the width of the object be? Let's try -9.5. Can we have an object with -9.5 width?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

I honestly think its that, it has to be greater than 0

OpenStudy (anonymous):

think of it in terms of mathematics though. What would happen if we had w=0 in that function?

OpenStudy (anonymous):

we've already eliminated w<0

OpenStudy (anonymous):

but it doesnt say less than or equal to, it just says greater than

OpenStudy (anonymous):

ignore the multiple choice answers for now, we need find the permissible values for w.

OpenStudy (anonymous):

we know w can't be less than zero, since that won't make sense for a real object.

OpenStudy (anonymous):

if w isn't smaller than zero, it's either zero, or bigger than zero.

OpenStudy (anonymous):

so we need to elminate zero as a possibility.

OpenStudy (anonymous):

what does the function tell you that lets you do this?

OpenStudy (sleepyjess):

@Xeph ... you are great at explaining things!

OpenStudy (anonymous):

thanks.

OpenStudy (anonymous):

the H(w)?

OpenStudy (anonymous):

\[H(w)=\frac{65}{w}\]

OpenStudy (anonymous):

why can't w be zero?

OpenStudy (anonymous):

because anything times 0 is zero

OpenStudy (anonymous):

it's because when you divide by zero, everything breaks

OpenStudy (anonymous):

simply speaking

OpenStudy (anonymous):

same reason we found asymptotes in your last question, when the denominator was zero

OpenStudy (anonymous):

therefore, w>0

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

you're welcome

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