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Mathematics 14 Online
OpenStudy (highschoolmom2010):

Use the given information to find the scale factor of the smaller figure to the larger figure.

OpenStudy (highschoolmom2010):

ganeshie8 (ganeshie8):

you're given Volumes of both figures

OpenStudy (anonymous):

x=small y=big scale of small to big = x/y

ganeshie8 (ganeshie8):

use this :- if volume are in ratio \(\large v_1 : v_2\), then sides will be in ratio \(\large \sqrt[3]{v_1} : \sqrt[3]{v_2}\)

OpenStudy (anonymous):

cancel out the pi*ft^3 from both and look at the constants for your ratio

OpenStudy (highschoolmom2010):

\[\sqrt[2]{250 \pi (ft)^3}:\sqrt[2]{432 \pi(ft)^3}\]

ganeshie8 (ganeshie8):

Yes !

OpenStudy (highschoolmom2010):

ok so what do i need to do nest

OpenStudy (highschoolmom2010):

next*

ganeshie8 (ganeshie8):

\(\large \sqrt[3]{250(ft)^3} : \sqrt[3]{432(ft)^3}\) \(\large \frac{\sqrt[3]{250(ft)^3}}{ \sqrt[3]{432(ft)^3}}\) \(\large \sqrt[3]{\frac{250(ft)^3}{ 432(ft)^3}}\) \(\large \sqrt[3]{\frac{250}{ 432}}\)

ganeshie8 (ganeshie8):

simplify

OpenStudy (highschoolmom2010):

oh ok

OpenStudy (highschoolmom2010):

is that a 3 before the sqrt

ganeshie8 (ganeshie8):

its called cube-root

ganeshie8 (ganeshie8):

wolfram says, scale factor = 5/6 http://www.wolframalpha.com/input/?i=%28250%2F432%29%5E%281%2F3%29

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