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OpenStudy (highschoolmom2010):
Use the given information to find the scale factor of the smaller figure to the larger figure.
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OpenStudy (highschoolmom2010):
ganeshie8 (ganeshie8):
you're given Volumes of both figures
OpenStudy (anonymous):
x=small
y=big
scale of small to big = x/y
ganeshie8 (ganeshie8):
use this :-
if volume are in ratio \(\large v_1 : v_2\), then sides will be in ratio \(\large \sqrt[3]{v_1} : \sqrt[3]{v_2}\)
OpenStudy (anonymous):
cancel out the pi*ft^3 from both and look at the constants for your ratio
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OpenStudy (highschoolmom2010):
\[\sqrt[2]{250 \pi (ft)^3}:\sqrt[2]{432 \pi(ft)^3}\]
ganeshie8 (ganeshie8):
Yes !
OpenStudy (highschoolmom2010):
ok so what do i need to do nest
OpenStudy (highschoolmom2010):
next*
ganeshie8 (ganeshie8):
\(\large \sqrt[3]{250(ft)^3} : \sqrt[3]{432(ft)^3}\)
\(\large \frac{\sqrt[3]{250(ft)^3}}{ \sqrt[3]{432(ft)^3}}\)
\(\large \sqrt[3]{\frac{250(ft)^3}{ 432(ft)^3}}\)
\(\large \sqrt[3]{\frac{250}{ 432}}\)
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ganeshie8 (ganeshie8):
simplify
OpenStudy (highschoolmom2010):
oh ok
OpenStudy (highschoolmom2010):
is that a 3 before the sqrt
ganeshie8 (ganeshie8):
its called cube-root
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