explain how all of the following expressions have the same answer.
well, they're all "blank", thus they all have the same answer, which is "blank", easy
haha yea sorry it took a while to put a picture up
what would you get when simplifying \(\bf \large \sqrt[3]{x^3}\quad ?\)
idk um x^1?
ok... so now let's see the following one \(\bf \large {\sqrt[3]{x^3}\implies x\\ \quad \\ x^{\frac{1}{3}}\cdot x^{\frac{1}{3}}\cdot x^{\frac{1}{3}}\implies x^{\frac{1}{3}+\frac{1}{3}+\frac{1}{3}=\frac{3}{3}=1}\implies x^1=x}\) what about the next one \(\bf \cfrac{1}{x^{-1}}\quad ?\)
i really dont know i dont get it
keep in mind that \(\bf a^{-n} = \cfrac{1}{a^n}\)
x^-1?
you could use this thinking: all have the same answer... the first two simplify to x so you should expect the remaining two will also simplify to x you now need the reason for this happens.
*why this happens
ok thank you
for the third on your list, see http://www.freemathhelp.com/negative-exponents.html It is just a "rule"
For the last one, see http://www.dummies.com/how-to/content/how-to-convert-square-roots-to-exponents0.html
thnk you so much that really helps
\(\bf \cfrac{1}{x^{-1}}\implies x^{-(-1)}\implies x^1=x\)
\(\bf \large \sqrt[11]{x^5\cdot x^4\cdot x^2}\implies \sqrt[11]{x^{5+4+2}}\) anyhow
yea and then that equals to \[\sqrt[11]{x ^{11}}\] then i get x
yeap
thank you
yw
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