Question

Help with Algebra 2?

[−1 −2]^3
[ 1 0]

Can I do that?

Answer 1

\[\left(\begin{matrix}-1&-2\\1&0\end{matrix}\right)\left(\begin{matrix}-1&-2\\1&0\end{matrix}\right)\left(\begin{matrix}-1&-2\\1&0\end{matrix}\right)\]\[=\left(\begin{matrix}-1\times(-1)+(-2)\times1&-1\times(-2)+(-2)\times0\\1\times(-1)+0\times1&1\times(-2)+0\times0\end{matrix}\right)\left(\begin{matrix}-1&-2\\1&0\end{matrix}\right)\]\[=\left(\begin{matrix}-1&2\\-1&-2\end{matrix}\right)\left(\begin{matrix}-1&-2\\1&0\end{matrix}\right)\]\[=\left(\begin{matrix}-1\times(-1)+2\times1&-1\times(-2)+2\times0\\-1\times(-1)+(-2)\times1&-1\times(-2)+(-2)\times0\end{matrix}\right)\]\[=\left(\begin{matrix}3&4\\-1&2\end{matrix}\right)\]

Remember the golden rule:
\[\left(\begin{matrix}a&b\\c&d\end{matrix}\right)\left(\begin{matrix}e&f\\g&h\end{matrix}\right)=\left(\begin{matrix}ae+bg&af+bh\\ce+dg&cf+dh\end{matrix}\right)\]

Answer 2

these are my options

Answer 3

Help?!?!?!?!?!?!?!

Answer 4

look what @kc_kennylau did

Answer 5

It isnt an option tho...

Answer 6

@helpme1.2

Answer 7

KC-math is a little off at line 4