Can someone solve and show work? Easy medal!
I think B is right, but dont quote me on it!
B is not correct, btw
o...my bad
I was thinking A, but I am not sure why.
2 * 3 = 6 For the x parts, add the exponents.
how do you know B isnt right?
\[(x^2)*(x^5)=(x*x)*(x*x*x*x*x)=x^7\] It appears the rule is to add exponents. What's 6+(1/2)?
Then A would make sense if Mathstudent55 is right
Obviously 3, but I don't think that is the correct way to solve it. I think mathstudent55 is on the right track.
6+1/2 is not 3.
This a test?
6*(1/2)=3
Oh, I thought you said 6 / 2 or times 1/2, my mistake. And no, it is a review. I did my review and missed six so I will probably post the other 5 to see my mistakes for the test.
o...I think A is right
@Monster143 why do you think that?
\(\Large(2x^6)(3x^{\frac{1}{2}}) \) \(= \Large2 \times 3 \times x^6 \times x^{\frac{1}{2}} \) \(= \Large 6 \times x^{6 + \frac{1}{2}} \) \(= \Large 6 \times x^{\frac{6}{1} + \frac{1}{2}} \) \(= \Large 6 x^{\frac{12}{2} + \frac{1}{2}} \) Now add the exponents since they already have a common denominator.
Very clear and concise, also correct. Thanks a ton!
the comment that mathstudent55 "put....2 * 3 = 6 For the x parts, add the exponents"
The answer is A
TaDa!
Well @mathstudent55 completely missed an opportunity to let them learn something. Sad.
huh? ^
I understood the basics and I know the rules for exponents, I was just confused because of the rational exponent. Thanks again.
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