Ask your own question, for FREE!
Algebra 16 Online
OpenStudy (anonymous):

Can someone solve and show work? Easy medal!

OpenStudy (anonymous):

OpenStudy (anonymous):

I think B is right, but dont quote me on it!

OpenStudy (anonymous):

B is not correct, btw

OpenStudy (anonymous):

o...my bad

OpenStudy (anonymous):

I was thinking A, but I am not sure why.

OpenStudy (mathstudent55):

2 * 3 = 6 For the x parts, add the exponents.

OpenStudy (anonymous):

how do you know B isnt right?

OpenStudy (kainui):

\[(x^2)*(x^5)=(x*x)*(x*x*x*x*x)=x^7\] It appears the rule is to add exponents. What's 6+(1/2)?

OpenStudy (anonymous):

Then A would make sense if Mathstudent55 is right

OpenStudy (anonymous):

Obviously 3, but I don't think that is the correct way to solve it. I think mathstudent55 is on the right track.

OpenStudy (kainui):

6+1/2 is not 3.

OpenStudy (anonymous):

This a test?

OpenStudy (kainui):

6*(1/2)=3

OpenStudy (anonymous):

Oh, I thought you said 6 / 2 or times 1/2, my mistake. And no, it is a review. I did my review and missed six so I will probably post the other 5 to see my mistakes for the test.

OpenStudy (anonymous):

o...I think A is right

OpenStudy (kainui):

@Monster143 why do you think that?

OpenStudy (mathstudent55):

\(\Large(2x^6)(3x^{\frac{1}{2}}) \) \(= \Large2 \times 3 \times x^6 \times x^{\frac{1}{2}} \) \(= \Large 6 \times x^{6 + \frac{1}{2}} \) \(= \Large 6 \times x^{\frac{6}{1} + \frac{1}{2}} \) \(= \Large 6 x^{\frac{12}{2} + \frac{1}{2}} \) Now add the exponents since they already have a common denominator.

OpenStudy (anonymous):

Very clear and concise, also correct. Thanks a ton!

OpenStudy (anonymous):

the comment that mathstudent55 "put....2 * 3 = 6 For the x parts, add the exponents"

OpenStudy (imstuck):

The answer is A

OpenStudy (anonymous):

TaDa!

OpenStudy (kainui):

Well @mathstudent55 completely missed an opportunity to let them learn something. Sad.

OpenStudy (anonymous):

huh? ^

OpenStudy (anonymous):

I understood the basics and I know the rules for exponents, I was just confused because of the rational exponent. Thanks again.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!