Question

I don't understand why my answer was wrong. Please help.

Answer 1

The first step is to deal with the exponent of -3.

Answer 2

\(\Large \left( \dfrac{a}{b} \right)^{n} = \dfrac{a^n}{b^n} \)

Answer 3

Actually I dealt with the -3 exponent last and worked within the paranthesis first.

Answer 4

The rule above means that you raise the numerator and the denominator to -3.

Answer 5

You can do it either way. In fact your way will be faster.

Answer 6

Yeah, I did it IMstuck's way and I think I got the right answer. B?

Answer 7

\[(\frac{ m ^{-1}m ^{5} }{ m ^{-2} })^{-3}\]

Answer 8

\[(\frac{ m ^{4} }{ m ^{-2} })^{-3}\]

Answer 9

\[(\frac{ m ^{4} }{ \frac{ 1 }{ m ^{2} } })^{-3}\]

Answer 10

\[(\frac{ m ^{4} }{ 1 }\times \frac{ m ^{2} }{ 1 })^{-3}\]

Answer 11

\[(m ^{6})^{-3}=m ^{-18}=\frac{ 1 }{ m ^{18} }\]

Answer 12

Do you see that and how it all works?

Answer 13

Yes, thanks so much. Your method eased confusion and gave the correct answer.

Answer 14

Very cool for you then! Good luck with it all!

Answer 15

\( \Large \left( \dfrac{m^{-1}m^{5}}{m^{-2}} \right)^{-3} \)

\( =\Large \left( m^{-1+5- (-2)} \right)^{-3} \)

\( =\Large \left( m^{-1+5+2} \right)^{-3} \)

\( =\Large \left( m^{6} \right)^{-3} \)

\( =\Large m^{6 \times (-3)} \)

\( =\Large m^{-18} \)

\( = \Large \dfrac{1}{m^{18}} \)