Question

Finding the derivative (Problem is in the comment)

Answer 1

I started it but got confused

Answer 2

Quotient rule?

Answer 3

I did that and I got a super long answer so Im not sure if I did it right

Answer 4

I got (x+3) (1(x^2-1)* 2x - (x^2-1)(1)/ (x+3)^2

Answer 5

Write it with the equation editor?

Answer 6

okay one second

Answer 7

\[\frac{ (x+3)(1(x ^{2}-1)*2x-(x ^{2}-1)(1) }{ (x+3)^{2} }\]

Answer 8

That's exactly right, but you just forgot the x in \[\LARGE (x^2-1)\]
Do you need to simplify it or no?

Answer 9

wait theres an x wheree?

Answer 10

\[\LARGE \frac{ (x+3)(1(x ^{2}-1)*2x-\color{red}{x}(x ^{2}-1)(1) }{ (x+3)^{2} }\]
Right there.

Answer 11

You forgot it.

Answer 12

whats with the brackets ??
(also it would have been easier if you did x(x^2-1) = x^3 -x instead of product for it.)

Answer 13

We haven't simplified yet, just did the proper steps of the quotient rule my good sir.

Answer 14

@mother123, make sense?

Answer 15

derivative of numerator
x^2-1 + 2x^2

\([x^2-1 + 2x^2] (x+3) - x (x^2-1)\)
this should be the numerator of the answer(which needs simplification)....

Answer 16

is that what u guys got ?