Finding the derivative (Problem is in the comment)

Question

anonymous · Answer

I started it but got confused

luigi0210 · Answer

Quotient rule?

anonymous · Answer

I did that and I got a super long answer so Im not sure if I did it right

anonymous · Answer

I got (x+3) (1(x^2-1)* 2x - (x^2-1)(1)/ (x+3)^2

luigi0210 · Answer

Write it with the equation editor?

anonymous · Answer

okay one second

anonymous · Answer

$$\frac{ (x+3)(1(x ^{2}-1)*2x-(x ^{2}-1)(1) }{ (x+3)^{2} }$$

luigi0210 · Answer

That's exactly right, but you just forgot the x in $$\LARGE (x^2-1)$$
Do you need to simplify it or no?

anonymous · Answer

wait theres an x wheree?

luigi0210 · Answer

$$\LARGE \frac{ (x+3)(1(x ^{2}-1)*2x-\color{red}{x}(x ^{2}-1)(1) }{ (x+3)^{2} }$$
Right there.

luigi0210 · Answer

You forgot it.

hartnn · Answer

whats with the brackets ??
(also it would have been easier if you did x(x^2-1) = x^3 -x instead of product for it.)

luigi0210 · Answer

We haven't simplified yet, just did the proper steps of the quotient rule my good sir.

luigi0210 · Answer

@mother123, make sense?

hartnn · Answer

derivative of numerator
x^2-1 + 2x^2 

$[x^2-1 + 2x^2] (x+3)  - x (x^2-1)$
this should be the numerator of the answer(which needs simplification)....

hartnn · Answer

is that what u guys got ?