Quadrilateral OPQR is inscribed inside a circle as shown below. What equation would be needed to solve for angle R? What is the measure of angle R? You must show all work and calculations to receive credit.
@cwrw238 help plz
@221emily help plz
Do you know the formula for the sum of the measures of the angles of a polygon?
Sum of Interior Angles = 180*(n-2) Individual Interior Angle = 180*(n-2)/n Sum of Exterior Angles = 360 Individual Exterior Angle = 360/n
Excellent. Since this is a quadrilateral, which has 4 sides, n = 4. What is the sum of the measures of the interior angles of this quadrilateral?
180*(4-2)=360
Great.
Now you know that the sum of the measures of the interior angles equals 360. That means when you add all the expressions you have for the interior angles, you get 360.
that is the answer?
2x + 3y + 8 + 2x + 4 + y = 360
You need another equation. gtg
@wolf1728 help
Ok, I'm back; I've thought about this problem some more, and I figured it out. The key here is that the quadrilateral is inscribed in a circle. |dw:1388436389109:dw| \(m<A = \dfrac{x}{2} \)
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