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Mathematics 8 Online
OpenStudy (calculusxy):

Four friends are going to sit in a row on a bench to have their picture taken. In how many different orders can the four friends sit?

OpenStudy (fibonaccichick666):

ooh! funzies!! So there are two ways to do this problem, logic or graphical, you pick

OpenStudy (calculusxy):

Logic. But if that doesn't work for me then I will chose graphical.

OpenStudy (fibonaccichick666):

k so let's name the friends 1,2,3,4 and the positions a,b,c,d respectively

OpenStudy (fibonaccichick666):

how many options do you have at position 1 when 2,3,4 are empty?

OpenStudy (calculusxy):

4?

OpenStudy (fibonaccichick666):

oops, position a, b,c,d are empty

OpenStudy (fibonaccichick666):

and yes 4 that is correct. now how many options do you have for position b once a is filled?

OpenStudy (calculusxy):

3? Since you can fill up the positions of b,c, and d.

OpenStudy (fibonaccichick666):

well 3 since you have 3 people left, but 3 is correct, now how about c?

OpenStudy (calculusxy):

2. Since c and d is empty.

OpenStudy (fibonaccichick666):

2 because you have people 3 and 4 left

OpenStudy (fibonaccichick666):

now d?

OpenStudy (calculusxy):

1

OpenStudy (fibonaccichick666):

k so we went from 4 to 3 to 2 to 1. if we multiply these that will give us the max permutation. this can also be denoted 4!

OpenStudy (fibonaccichick666):

!=factorial

OpenStudy (calculusxy):

What does permutation mean?

OpenStudy (fibonaccichick666):

permutation is the number of ways a group can be mixed up with the order mattering. combination means order doesn't matter (i might have those backwards)

OpenStudy (fibonaccichick666):

yep just checked, is this for an abstract algebra class per chance?

OpenStudy (calculusxy):

No I am just learning. :)

OpenStudy (fibonaccichick666):

ahh ok well i suggest MIT opencourseware for a video class it's pretty sweet

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