Question

What is the length of the longest side of a triangle that has vertices at (-3, -2), (2, -2), and (-3, -7)?

Answer 1

Do you know the distance formula?
Use it between each two points.

Answer 2

The distance, d, between points \( (x_1, y_1) \) and \((x_2, y_2) \) is given by the distance formula below

\( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \)

Answer 3

In this case, since you already graphed it, you can see it's a right triangle.
That means the longest side is the hypotenuse.
Then all you need to do is to find the length of the hypotenuse.

The hypotenuse is the side opposite the right angle. It's the side with vertices (2, -2) and (-3, -7). Use the distance formula for those two points.

Answer 4

\[d=\sqrt{(_{x2-_{x1)^{2+(y ^{2-y ^{1)^{2}}}}}}}\]

Answer 5

I can write very well this type of system, not sorry

Answer 6

Copy the line below and paste it and place \( before and after it..
Then paste it again, and replace the x's and y's with the actual coordinates.
Then write \( before and after the line to get the LaTex code.

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}