Question

MEDALS!!!!!!!!
Systems of Equations
A system of equations is shown below.

8x + 5y = 9
3x + 2y = 4

Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this.
Part B: Show that the equivalent system has the same solution as the original system of equations.

Answer 1

8x + 5y = 9 so you can eliminate variables, multiply this equation by -3
-24x + -15y = -27

3x+2y = 4 multiply this equation by 8
24x + 16y = 32

No combine the two equations: -24x + -15y = -27
24x + 16y = 32
y = 5

To find x, substitute 5 into the equations for y

Answer 2

Would that be Part A?

Answer 3

8x + 5(5) = 9
8x = -16
x =- 2 The solution to the system is (-2,5)

Answer 4

So for example in Part B it would be 8(-2) + 5(5) = 9??

Answer 5

That's part B

Answer 6

How did you get that??

Answer 7

It's ok, I was just wondering how you got those weird numbers

Answer 8

Be sure to show that in both of the original equations

Answer 9

Wait, is that Part B?? I thought you said that it was wrong??

Answer 10

No..you were right. I was goofed up

Answer 11

Ok thank you @DSS

Answer 12

8(-2) + 5(5) = 9
-16 + 25 = 9
9 = 9
3x + 2y = 4

3(-2)+2(5)=4
-6+10=4
4 = 4

Part B