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Chemistry 20 Online
OpenStudy (anonymous):

Butane(C4H10) burns. Balanced Equation? Don't understand this stuff!!!!Help Please!!!

OpenStudy (australopithecus):

When you burn stuff you are reacting it with oxygen! so it is one of your reactants. After complete combustion of a hydrocarbon you end up with CO2 and H2O

OpenStudy (australopithecus):

Can you write out the reaction now?

OpenStudy (anonymous):

That is the thing is the problem you are looking for is the reaction.. sorry...

OpenStudy (australopithecus):

Have you seen a chemical reaction before?

OpenStudy (australopithecus):

I just told you what the products and reactants are

OpenStudy (australopithecus):

oops I mean chemical equation

OpenStudy (australopithecus):

An example of a chemical equation: A + B -> C Reactants are on the left, Products are on the right

OpenStudy (australopithecus):

I'm not here to give you the answer but I will guide you to it. If you dont understand my explanation please tell me which part of it is not clear to you?

OpenStudy (anonymous):

so it would be O2+(combustion of hydrocarbon)-> CO2 + H20?

OpenStudy (australopithecus):

O2+(hydrocarbon)-> CO2 + H20?

OpenStudy (australopithecus):

fixed

OpenStudy (anonymous):

what is the hydro carbon in chemical form? does that make sense?

OpenStudy (australopithecus):

a hydrocarbon is a class of molecules composed entirely of Carbon and Hydrogen, an example is butane, octane, methane etc

OpenStudy (australopithecus):

oh and benzene

OpenStudy (australopithecus):

so if you see something with C, H and in some cases O, then you can assume it is H2O + CO2

OpenStudy (australopithecus):

Carbohydrates (also known of sugars) are also hydrocarbons but they contain oxygen as well

OpenStudy (australopithecus):

Sorry if you didnt understand what I meant by hydrocarbon do you understand now?

OpenStudy (australopithecus):

When you combust something you are reacting it with O2 gas

OpenStudy (australopithecus):

so can you write out your reaction now?

OpenStudy (australopithecus):

Then I will help you with balancing (dont worry it is super easy)

OpenStudy (anonymous):

C4H10 + O2 => CO2 + H2O

OpenStudy (australopithecus):

:) right

OpenStudy (australopithecus):

also I forgot to mention you should show which phase each chemical is in, like so, C4H10(g) + O2(g) => CO2(g) + H2O(l) g stands for gas, l stands for liquid, s stands for solid

OpenStudy (australopithecus):

so now you need to balance the equation, you need the same amount of atoms on both side of the equation, so that the chemical reaction follows the law of conservation of mass

OpenStudy (australopithecus):

This law states that the mass does not change in a chemical reaction

OpenStudy (anonymous):

Would you put a 4 in front of the CO2 to balance the Carbon and a 5 in front of the Oxygen so they were all balanced? Or does that not make the Hydrogen balanced? so the equation would be: C4H10(g)+ 5O2(g)=> 4CO2(g) + H20 (l)?

OpenStudy (australopithecus):

Oops there shouldnt be a 4 in front of CO2 in the first part

OpenStudy (australopithecus):

but I hope you see my method

OpenStudy (anonymous):

could you put into a equation I understand reading them that way..

OpenStudy (australopithecus):

C4H10(g) + O2(g) => CO2(g) + H2O(l) Right now, Products: 4 C, 10 H, 2O Reactants: 1C, 3O, 1H so balance the carbons by multiplying the CO2 by 4 C4H10(g) + O2(g) => 4CO2(g) + H2O(l) Now we have, Products: 4 C, 10 H, 2O Reactants: 4C, 9O, 1H and you keep going like this until both sides have the same number of atoms

OpenStudy (australopithecus):

Just read what I wrote you, if you follow my method you wont be steered wrong

OpenStudy (australopithecus):

There probably exists some equation, but I do not know it and it is not like this method is particularly hard.

OpenStudy (australopithecus):

If an equation does exist I don't think it is worth memorizing.

OpenStudy (australopithecus):

The thing about learning is that not everything will be given to you in the clearest of manor, you will have to get use to this. Although in this case you could just visit https://www.youtube.com/watch?v=RnGu3xO2h74

OpenStudy (anonymous):

thanks

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