What is the inverse of f if….
\[f(3) \sqrt[3]{x-2}\]
\[f(x)=\sqrt[3]{x-2}\] ?
\[f(3)=\sqrt[3]{x-2}\]
i forgot to put an = sign the first time
are we finding f'(3) either way to get the inverse, let's replace f(x) with y \[y = \sqrt[3]{x-2}\] switch x and y \[x = \sqrt[3]{y-2}\] cube both sides \[x^3 = {y-2}\] \[x^3+2=y\]
\[x^{3}+2=y^{3}\] is that right?.. i have no idea I'm so stressed
How'd you get y^3? Remember that square roots and squares are inverse operations, right? \[(\sqrt{x})^2 = x\] \[(\sqrt[3]{x})^3 = x\]
oh i got confused i thought you said for ME to cube both sides lol. I'm sorry I'm extremely tired and have to get a bunch of work done by like tomorrow. ughhh. my bad
lol no worries, just always go over your work a bazillion times so that you can prove to yourself that your answer is right. ANYHOW, the inverse is now f(x) =x^2+2 f(3) = 3^2+2 = ??
wait so the answer is f(x) =x^2+2 ?
whoops./ you generally say inverse with a little dash f'(x) so the equation for the inverse is f'(x) = x^2 + 2 then you plug in 3 into the inverse equation (assuming that's the question)
heres the actual question with the answer choices so you can see
god damn. I kept saying x^2 +2 but I meant x^3 + 2
hahah so is it the 3rd option then?
it is, it is...
thank youuu! i have another question! do you mind helping me??
are you gonna post it here or make a new question? I don't mind
ill post it here! and thanks! (:
uh you'd multiply by the conjugate. pardon my handwriting
i dont understand...
to simplify radicals you multiply by the conjugate pair which means flipping the sign
why do you have that answer selected?
what do you mean that answer selected?
what are the answer choices?
the ones with the bubble next to them on the link i posted!
rofl I didn't see it scrolled down a bit.
hahahah its all good! (:
so what is the answer?
Perform the operation bibby suggested and then simplify.
you can use wolfram if you don't like learning http://www.wolframalpha.com/input/?i=%28sqrt%283%29-sqrt%286%29%29%2F%28sqrt%283%29%2Bsqrt%286%29%29
its not that i don't like learning its that i am in a hurry and i have no idea whats going on.
\[\frac{\sqrt{3}-\sqrt{6}}{\sqrt{3}+\sqrt{6}} \cdot \frac{\sqrt{3}-\sqrt{6}}{\sqrt{3}-\sqrt{6}}\] Do this multiplication here.
Why are you in a hurry? Is this a test?
idk how to..
i had to go out of town so I'm behind on a bunch of work due like really soon
So you don't know how to multiply something like this (a+b)(c+d)?
A lot of Americans like to use this thing called the foil method.
i have heard of it but idk how to really use it
(a+b)(c+d)=ac+ad+bc+bd
all you did was distribute those right?
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