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Mathematics 13 Online
OpenStudy (anonymous):

What is the inverse of f if….

OpenStudy (anonymous):

\[f(3) \sqrt[3]{x-2}\]

OpenStudy (bibby):

\[f(x)=\sqrt[3]{x-2}\] ?

OpenStudy (anonymous):

\[f(3)=\sqrt[3]{x-2}\]

OpenStudy (anonymous):

i forgot to put an = sign the first time

OpenStudy (bibby):

are we finding f'(3) either way to get the inverse, let's replace f(x) with y \[y = \sqrt[3]{x-2}\] switch x and y \[x = \sqrt[3]{y-2}\] cube both sides \[x^3 = {y-2}\] \[x^3+2=y\]

OpenStudy (anonymous):

\[x^{3}+2=y^{3}\] is that right?.. i have no idea I'm so stressed

OpenStudy (bibby):

How'd you get y^3? Remember that square roots and squares are inverse operations, right? \[(\sqrt{x})^2 = x\] \[(\sqrt[3]{x})^3 = x\]

OpenStudy (anonymous):

oh i got confused i thought you said for ME to cube both sides lol. I'm sorry I'm extremely tired and have to get a bunch of work done by like tomorrow. ughhh. my bad

OpenStudy (bibby):

lol no worries, just always go over your work a bazillion times so that you can prove to yourself that your answer is right. ANYHOW, the inverse is now f(x) =x^2+2 f(3) = 3^2+2 = ??

OpenStudy (anonymous):

wait so the answer is f(x) =x^2+2 ?

OpenStudy (bibby):

whoops./ you generally say inverse with a little dash f'(x) so the equation for the inverse is f'(x) = x^2 + 2 then you plug in 3 into the inverse equation (assuming that's the question)

OpenStudy (anonymous):

heres the actual question with the answer choices so you can see

OpenStudy (bibby):

god damn. I kept saying x^2 +2 but I meant x^3 + 2

OpenStudy (anonymous):

hahah so is it the 3rd option then?

OpenStudy (bibby):

it is, it is...

OpenStudy (anonymous):

thank youuu! i have another question! do you mind helping me??

OpenStudy (bibby):

are you gonna post it here or make a new question? I don't mind

OpenStudy (anonymous):

ill post it here! and thanks! (:

OpenStudy (anonymous):

OpenStudy (bibby):

uh you'd multiply by the conjugate. pardon my handwriting

OpenStudy (anonymous):

i dont understand...

OpenStudy (bibby):

to simplify radicals you multiply by the conjugate pair which means flipping the sign

OpenStudy (bibby):

why do you have that answer selected?

OpenStudy (anonymous):

what do you mean that answer selected?

OpenStudy (bibby):

what are the answer choices?

OpenStudy (anonymous):

the ones with the bubble next to them on the link i posted!

OpenStudy (bibby):

rofl I didn't see it scrolled down a bit.

OpenStudy (anonymous):

hahahah its all good! (:

OpenStudy (anonymous):

so what is the answer?

myininaya (myininaya):

Perform the operation bibby suggested and then simplify.

OpenStudy (bibby):

you can use wolfram if you don't like learning http://www.wolframalpha.com/input/?i=%28sqrt%283%29-sqrt%286%29%29%2F%28sqrt%283%29%2Bsqrt%286%29%29

OpenStudy (anonymous):

its not that i don't like learning its that i am in a hurry and i have no idea whats going on.

myininaya (myininaya):

\[\frac{\sqrt{3}-\sqrt{6}}{\sqrt{3}+\sqrt{6}} \cdot \frac{\sqrt{3}-\sqrt{6}}{\sqrt{3}-\sqrt{6}}\] Do this multiplication here.

myininaya (myininaya):

Why are you in a hurry? Is this a test?

OpenStudy (anonymous):

idk how to..

OpenStudy (anonymous):

i had to go out of town so I'm behind on a bunch of work due like really soon

myininaya (myininaya):

So you don't know how to multiply something like this (a+b)(c+d)?

myininaya (myininaya):

A lot of Americans like to use this thing called the foil method.

OpenStudy (anonymous):

i have heard of it but idk how to really use it

myininaya (myininaya):

(a+b)(c+d)=ac+ad+bc+bd

OpenStudy (anonymous):

all you did was distribute those right?

myininaya (myininaya):

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