Mathematics
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OpenStudy (anonymous):
Max-Min problem please help
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OpenStudy (kc_kennylau):
Two hongkongers coming to help you xD *laughcry*
OpenStudy (kc_kennylau):
@Callisto and I come from Hong Kong :)
OpenStudy (kc_kennylau):
yay xD
OpenStudy (kc_kennylau):
\[C=\left\{\begin{array}{lr}50x&\mbox{if }x\le10\\(50-0.5(x-10))x=(55-0.5x)x&\mbox{if }x>10\end{array}\right.\]
OpenStudy (anonymous):
do we find the first derivative of this???
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OpenStudy (anonymous):
55-x
OpenStudy (kc_kennylau):
This function is discontinuous and non-differentiatable, are you telling me to differentiate it xD
OpenStudy (anonymous):
i need to find the x and what is the maximum total group charge to the company
OpenStudy (kc_kennylau):
what's the maximum of (55-0.5x)x... hmm...
OpenStudy (kc_kennylau):
yep, sorry, differentiation will work. Solve for c'(x)=0 :)
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OpenStudy (anonymous):
sorry i dont understand this still its really hard for me because i m not in calculus
OpenStudy (callisto):
Do you know completing square?
OpenStudy (callisto):
Do you know how to find the vertex a quadratic graph?
OpenStudy (anonymous):
yes
OpenStudy (callisto):
Just from a given quadratic equation?
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OpenStudy (anonymous):
yes
OpenStudy (callisto):
Then, what is the vertex of (55-0.5x)x = 0?
OpenStudy (anonymous):
(55,1512.5)
OpenStudy (callisto):
Right. Since the graph opens downwards, the y-coordinate gives you the maximum value of the function.
OpenStudy (anonymous):
ok the x=55 and the maximum total group charge to the company is 1512.5
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OpenStudy (callisto):
I guess that's it.
OpenStudy (anonymous):
ok thank you :)
OpenStudy (callisto):
Thanks @kc_kennylau