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Mathematics 14 Online
OpenStudy (anonymous):

Max-Min problem please help

OpenStudy (kc_kennylau):

Two hongkongers coming to help you xD *laughcry*

OpenStudy (kc_kennylau):

@Callisto and I come from Hong Kong :)

OpenStudy (kc_kennylau):

yay xD

OpenStudy (kc_kennylau):

\[C=\left\{\begin{array}{lr}50x&\mbox{if }x\le10\\(50-0.5(x-10))x=(55-0.5x)x&\mbox{if }x>10\end{array}\right.\]

OpenStudy (anonymous):

do we find the first derivative of this???

OpenStudy (anonymous):

55-x

OpenStudy (kc_kennylau):

This function is discontinuous and non-differentiatable, are you telling me to differentiate it xD

OpenStudy (anonymous):

i need to find the x and what is the maximum total group charge to the company

OpenStudy (kc_kennylau):

what's the maximum of (55-0.5x)x... hmm...

OpenStudy (kc_kennylau):

yep, sorry, differentiation will work. Solve for c'(x)=0 :)

OpenStudy (anonymous):

sorry i dont understand this still its really hard for me because i m not in calculus

OpenStudy (callisto):

Do you know completing square?

OpenStudy (callisto):

Do you know how to find the vertex a quadratic graph?

OpenStudy (anonymous):

yes

OpenStudy (callisto):

Just from a given quadratic equation?

OpenStudy (anonymous):

yes

OpenStudy (callisto):

Then, what is the vertex of (55-0.5x)x = 0?

OpenStudy (anonymous):

(55,1512.5)

OpenStudy (callisto):

Right. Since the graph opens downwards, the y-coordinate gives you the maximum value of the function.

OpenStudy (anonymous):

ok the x=55 and the maximum total group charge to the company is 1512.5

OpenStudy (callisto):

I guess that's it.

OpenStudy (anonymous):

ok thank you :)

OpenStudy (callisto):

Thanks @kc_kennylau

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