Question

How do I rewrite sin^(4)xtan^(2)x in terms of the first power of cosine?

Answer 1

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Answer 2

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Answer 3

\[\sin^4 x \tan^2x = \sin^4 x \frac {\sin^2x}{\cos^2x} = \frac {(\sin^2x)^3}{\cos^2x} =\frac {(1-\cos^2x)^3}{\cos^2x}\]

Simplify it then the final answer is:
\[-\cos^6x+3\cos^4x-3\cos^2x+1\]