Are there any angles x and y that satisfy sin(x+y)=sinx+siny ? Use an example to explain your answer @kc_kennylau
Expand the LHS using the formulae hereeeee :) http://www.a-levelmathstutor.com/images/trigonometry/ca-identities01.jpg
:(
Just changed the name of the variables, ain't a big deal xD
sin A + sin B
can you help me to replace x as A and y as B in the third formula? :)
I did ^^
the whole formula...
\[\sin(A+B)=\sin A\cos B+\cos A\sin B\] Replace the whole formula, A->x and B->y
Sin(x+y)= sinxcosy+cosxsiny
exactly
yay :D
So can you substitute what you wrote to the left hand side of \(\sin(x+y)=\sin x+\sin y\)? :)
Idk
what you mean
So you have \(\sin(x+y)=\sin x\cos y+\cos x\sin y\) and \(\sin (x+y)=\sin x+\sin y\), what can you say about them? :)
that they're very similar :P
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If \(a=b\) and \(a=c\), wha can you say about \(b\) and \(c\)?
its equal to A !!!
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they can equal each other
:\
exactlyyyyyyyyyyyyyyyyyyyyyyyy :DDDDDDD
ohhhh
so can you summarize what I've just learned ?? thanks
So if \(\color{blue}{\sin(x+y)}=\color{red}{\sin x\cos y+\cos x\sin y}\) and \(\color{blue}{\sin(x+y)}=\color{green}{\sin x+\sin y}\), what can you say about \(\color{red}{\sin x\cos y+\cos x\sin y}\) and \(\color{green}{\sin x+\sin y}\)?
you've learnt that when the thing inside \(\sin\) or \(\cos\) is made up of two substances that are the same or different, you can always use the formulae hereeeeeeeeeeeeeeeeeeee xD http://www.a-levelmathstutor.com/images/trigonometry/ca-identities01.jpg
omg not that link again >.<
but you have to memorize every. single. formula. of the website.......
yes yes
so the example we've used would be ???? what
would be the first formula used in the previous post, and the third formula being used now :D
what was the formula from the first tag ??
what do you mean first taggggg
first post !
you said it above
:'(
uh, it's the first formula \(\cos(A+B)=\cos A\cos B-\sin A\sin B\)
ok thanks for putting up with my lack of skils in math
:)
no problem :D
@kc_kennylau oh one more thing !
how would I convert the angle 4 to degrees???
\[\fbox{radian}=\fbox{degree}\times\frac\pi{180^\circ}\]\[\fbox{degree}=\fbox{radian}\times\frac{180^\circ}\pi\]
would it be 1pi/43?
@kc_kennylau
was the 4 in radian?
ikd it says convert following angles to degree measures
then i assume that it's radian
so is that the right answer that I got above?
nope :/
what is it?
The formula is \(\fbox{degree}=\fbox{radian}\times\dfrac{180^\circ}\pi\)
Substitute the \(\fbox{radian}\) as 4 :)
229.18
yep :)
thankss
:D<3
no problem <3
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