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Mathematics 7 Online
OpenStudy (anonymous):

Can someone explain how to do this?

OpenStudy (anonymous):

A chemist needs to mix a 12% acid solution with a 32% acid solution to obtain an 8-liters mixture consisting of 20% acid. How many liters of each of the acid solutions must be used?

OpenStudy (anonymous):

I need to know, pliz? Anyone that's good enough at math?

OpenStudy (anonymous):

we have 2 different Acid . yea ?

OpenStudy (anonymous):

K

OpenStudy (anonymous):

Again ;)

OpenStudy (anonymous):

Alright....

OpenStudy (anonymous):

did you understand question ?

OpenStudy (anonymous):

I did.

OpenStudy (anonymous):

What things question wants ?

OpenStudy (anonymous):

i AM OUT OF HERE! What do you think? I'll make a new question and tag better helpers... tnx for the help.

OpenStudy (anonymous):

!!! sorry me !

OpenStudy (anonymous):

I want to help u ;)

OpenStudy (anonymous):

You are wasting my time like crazy....

OpenStudy (anonymous):

No no ...! never ! Sorry me friend ...

OpenStudy (zpupster):

.12ofxLiters .32of y liters total volume is 8 L so x+y=8 and .12x+.32y = .2 of 8L we have 2 equations x+y=8 .12x+.32y =.1.6 make it easier mult 2nd equation by 100 x+y=8 12x+32y =160 lets use the elimination methos mult first equaiotn by 12 and subtract one from the other 12x+12y=96 12x+32y =160 20y=64 y=3.2 y= 3.2L do the check and subbing 8-3.2=x x=4.8L

OpenStudy (radar):

Good job @zpupster

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